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bazarr/libs/apprise/utils/logic.py
2025-01-18 10:02:09 -05:00

122 lines
4.5 KiB
Python

# -*- coding: utf-8 -*-
# BSD 2-Clause License
#
# Apprise - Push Notification Library.
# Copyright (c) 2025, Chris Caron <lead2gold@gmail.com>
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions are met:
#
# 1. Redistributions of source code must retain the above copyright notice,
# this list of conditions and the following disclaimer.
#
# 2. Redistributions in binary form must reproduce the above copyright notice,
# this list of conditions and the following disclaimer in the documentation
# and/or other materials provided with the distribution.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
# AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
# IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
# ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER OR CONTRIBUTORS BE
# LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
# CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
# SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS
# INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
# CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE)
# ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
# POSSIBILITY OF SUCH DAMAGE.
from itertools import chain
from .. import common
from .parse import parse_list
def is_exclusive_match(logic, data, match_all=common.MATCH_ALL_TAG,
match_always=common.MATCH_ALWAYS_TAG):
"""
The data variable should always be a set of strings that the logic can be
compared against. It should be a set. If it isn't already, then it will
be converted as such. These identify the tags themselves.
Our logic should be a list as well:
- top level entries are treated as an 'or'
- second level (or more) entries are treated as 'and'
examples:
logic="tagA, tagB" = tagA or tagB
logic=['tagA', 'tagB'] = tagA or tagB
logic=[('tagA', 'tagC'), 'tagB'] = (tagA and tagC) or tagB
logic=[('tagB', 'tagC')] = tagB and tagC
If `match_always` is not set to None, then its value is added as an 'or'
to all specified logic searches.
"""
if isinstance(logic, str):
# Update our logic to support our delimiters
logic = set(parse_list(logic))
if not logic:
# If there is no logic to apply then we're done early; we only match
# if there is also no data to match against
return not data
if not isinstance(logic, (list, tuple, set)):
# garbage input
return False
if match_always:
# Add our match_always to our logic searching if secified
logic = chain(logic, [match_always])
# Track what we match against; but by default we do not match
# against anything
matched = False
# Every entry here will be or'ed with the next
for entry in logic:
if not isinstance(entry, (str, list, tuple, set)):
# Garbage entry in our logic found
return False
# treat these entries as though all elements found
# must exist in the notification service
entries = set(parse_list(entry))
if not entries:
# We got a bogus set of tags to parse
# If there is no logic to apply then we're done early; we only
# match if there is also no data to match against
return not data
if len(entries.intersection(data.union({match_all}))) == len(entries):
# our set contains all of the entries found
# in our notification data set
matched = True
break
# else: keep looking
# Return True if we matched against our logic (or simply none was
# specified).
return matched
def dict_full_update(dict1, dict2):
"""
Takes 2 dictionaries (dict1 and dict2) that contain sub-dictionaries and
gracefully merges them into dict1.
This is similar to: dict1.update(dict2) except that internal dictionaries
are also recursively applied.
"""
def _merge(dict1, dict2):
for k in dict2:
if k in dict1 and isinstance(dict1[k], dict) \
and isinstance(dict2[k], dict):
_merge(dict1[k], dict2[k])
else:
dict1[k] = dict2[k]
_merge(dict1, dict2)
return