✨ Add support for declaring UploadFile parameters without explicit File() (#4469)

2026-03-28 19:56:40 -04:00 · 2022-01-23 20:14:13 +01:00
parent 59b1f353b3
commit 1bf55200a9
16 changed files with 1086 additions and 30 deletions
--- a/docs_src/request_files/tutorial003.py
+++ b/docs_src/request_files/tutorial003.py
@@ -0,0 +1,37 @@
+from typing import List
+
+from fastapi import FastAPI, File, UploadFile
+from fastapi.responses import HTMLResponse
+
+app = FastAPI()
+
+
+@app.post("/files/")
+async def create_files(
+    files: List[bytes] = File(..., description="Multiple files as bytes")
+):
+    return {"file_sizes": [len(file) for file in files]}
+
+
+@app.post("/uploadfiles/")
+async def create_upload_files(
+    files: List[UploadFile] = File(..., description="Multiple files as UploadFile")
+):
+    return {"filenames": [file.filename for file in files]}
+
+
+@app.get("/")
+async def main():
+    content = """
+<body>
+<form action="/files/" enctype="multipart/form-data" method="post">
+<input name="files" type="file" multiple>
+<input type="submit">
+</form>
+<form action="/uploadfiles/" enctype="multipart/form-data" method="post">
+<input name="files" type="file" multiple>
+<input type="submit">
+</form>
+</body>
+    """
+    return HTMLResponse(content=content)